-8x^2+32x+360=0

Solution for -8x^2+32x+360=0 equation:

-8x^2+32x+360=0

a = -8; b = 32; c = +360;
Δ = b2-4ac
Δ = 322-4·(-8)·360
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-112}{2*-8}=\frac{-144}{-16}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+112}{2*-8}=\frac{80}{-16}
=-5
$